plfoki.blogg.se

A constant eastward horizontal force of 70
A constant eastward horizontal force of 70






a constant eastward horizontal force of 70
  1. #A CONSTANT EASTWARD HORIZONTAL FORCE OF 70 HOW TO#
  2. #A CONSTANT EASTWARD HORIZONTAL FORCE OF 70 PLUS#

The distance of COM forward of the axle, and W the weight of

#A CONSTANT EASTWARD HORIZONTAL FORCE OF 70 PLUS#

Notated 2 S as the distance between the wheels, L theĭistance from the axle to the tongue support, q the distanceįrom the ground to the center of mass (COM ©) of the boat plus trailer, d (noting that I have made the boat on the trailer invisible!): I have Once, lifting one wheel at a time will introduce errors. Table weight answer, makes me think maybe it could be.Īssuming that you do not have three scales which could be all engaged at

#A CONSTANT EASTWARD HORIZONTAL FORCE OF 70 HOW TO#

I've been trying to figure out how to weigh my boat on its trailer, and it seemed to me that putting a scale under each of the two wheels and the tongue and adding the three weights together might not yield a correct result, but your Upwards until he has risen another h=½ v 2/ g=0.84 M/s if the weight is stopped after the 1.5 s, he will continue moving Mind that the speed of the actor at the end of the 1.5 s is v=at=2.7x1.5=4.05

a constant eastward horizontal force of 70

Same magnitude of acceleration as the actor: Mg-T=Ma, so Finally sum forces for the weight Mg which has the N where g=9.8 m/s 2 is the acceleration due to (assuming the mass of the pulley is negligible), Newton's second law isĢ T-mg= ma or T=½ m( g+a)=½x80x(9.8+2.7)=500 Choosing the man plus pulley above him as the body The actor will experience an accelleration a such that he moves a I'm coordinating a piece of action for a tvc (tv ad), which requires me to build a rig to raise an actor 3 m off the ground, as if he is being taken away by aliens! It's been a long time since school for me, however I feel that there would be a formula that would assist me in calculating how much counterweight is required on a pulley system with 2:1 MA to raise an 80kg actor 3m in 1.5 seconds?Īre you able to clarify the principals to be used in calculating this problem? Made of a material designed to melt when the heat up, essentially gluing Dragsters have "bald" tires because they are Increasing surface area does not increase traction because theįrictional force for dry friction depends only how hard the shoe isīeing pressed to the floor (your weight) and the coefficient of frictionīetween wood and rubber. Treads on a road tire channel water away to prevent hydroplaningĪnd I assume that would be the case for shoe treads as well. However,īecause of players sweating there is always a chance of hitting a wet If the floor is always perfectly dry, there is no reason. I get why shoes for outdoor activities do but wouldn't a basketball shoe work with no tread like race car tires. Hello I have been wondering why basketball shoes have tread. Work done by friction, regardless of the path, is W f= μmgL. The work done is W f=fs=( μmgcos θ)( L 2/cos θ)= μmgL 2,Įxactly the same as if the slope was not there. When the ball is moving forwardĪlong along the segment L 2, the distance Where the negative sign indicates that the friction takesĮnergy away from the ball. Specifically the work done by friction is W f=- fs Product with the distance s over which it acts, But, what matters is not the force but its Slope, you might think that less energy is lost to friction Since the frictional force is smaller on the Is the mass of the ball, and g is the accelerationĭue to gravity. I believe, what is measured by the "stimp meter"), m Here μ is the coefficient of friction (essentially, Will be different than on level ground ( f=μmg) However, there is friction which will slow the ball furtherĪnd the frictional force on a slope ( f=μmgcos θ) Would make no difference how the rise occurred, only theĪmount of rise. Ground rises 8 inches, and then drops 2 inches and thenįlattens out the rest of the way to the hole.same speed? You have the same 20 foot putt but halfway to the hole the Putts the same initial speed? Follow up question : What if Inches gently from the ball to the hole at a constant Of 6 inches right after you hit it, and then travels don't worry about things like theĪnd then shortly before the hole, it rises 6 inches. Let's say in all cases, the green isįlat after the hole. Seconds or so) to find the appropriate bookmark. Since the files containing the olderĪnswers are rather large, it takes some time (maybe as much as 15 If you like my answer, please consider making aĪnswered question, be patient. Is a history of questions and answers processed by "Ask the Physicist!". there are now threeĪsk the Physicist books! Click on the book images below for information on the content of the books and for information on ordering. With the recent publication of PHYSICS IS.








A constant eastward horizontal force of 70